Electrónica
EJERCIÓ #1
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T1
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T2
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T1 = A'B'C'+A'+B'C+A'BC'
=A'(B'C'+B'C+BC')
=A(C'(B'+B)+B'C)
=A'(C'+B'C)
=A'C'+A'B'
COMPROBACIÓN:
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C
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A'C'
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A'B'
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T1
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PODEMOS OBSERVAR SU IGUALDAD
AHORA PROCEDEREMOS COM T2
T2 =A'BC+AB'C'+AB'C+ABC'+ABC
=A'BC+AC'(B'+B)+AC(B'+B)
=A'BC+AC'+AC
=A'BC+A(C'+C)
=A'BC+A
COMPROBACIÓN
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C
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BC
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A'BC
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T2
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1
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1
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EJERCIO#2
T1=((AB)'A)((AB)'B)
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(AB)'
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(AB)'A
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(AB)'B
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T1
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VAMOS A SIMPLIFICAR Y A VER SI NOS SALE
EL MISMO RESULTADO
T1 =((AB)'A)((AB)'B)
USAMOS EL COMPLENTO QUE NO ES OTRA COSA
QUE LA NEGACIÓN DE TODO
=(((AB)'A)((AB)'B))'
=(AB+A')+(AB+B')
=(A'+B)+(B'+A)
=1
COMO LA COMPLEMENTACIÓN ES LA NEGACIÓN
EL RESULTADO DE
T1=0 SI MIRAMOS LA TABLA
VEMOS QUE ESO ES LO QUE NOS DA
EJERCICIO#3
T1=(A+C+D)(A+C+D')(A+B')
PARA SABER CUANTOS 0 Y UNOS USAREMOS
HACEMOS LO SIGUIENTE
2n=24 =16
ENTONCES SON 8 0 Y 8 1
A
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B
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C
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D
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A+C+D
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A+C+D'
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A+B'
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X
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T1
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SIMPLIFICACIÓN
T1
=(A+C+D)(A+C+D')(A+B')
T1'
=((A+C+D)(A+C+D')(A+B'))'
=A'C'D'+A'C'D+A'CD'+A'B
=A'(C'D'+C'D+CD'+B)
=A'(C'(D'+D)+CD'+B)
=A'(C'+CD'+B)
=A'C'+A'CD'+A'B
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B
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D
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A'D'
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A'C'
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A'CD'
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A'B
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T1'
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T1
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